Answer: No value for x
Step-by-step explanation:
Open the bracket
2x-6=2×+5; combine like terms
2×-2×=5+6
0=11
Answer:

Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean
kilograms and standard deviation
kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and 
And the best way to solve this problem is using the normal standard distribution and the z score given by:

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:

So then the corresponding z scale would be:

Answer:
B) Rotation
Step-by-step explanation:
A:40%
If you put 60 over 150 and x(percent of students) over 100 and cross multiply 100 and 60, you will get 6000. You then divide that by 150 which leaves you with 40 as x and 40 over 100 is 40%.
9514 1404 393
Answer:
(0, π/4] ∪ (π, 5π/4]
Step-by-step explanation:
Multiplying by 2 gives ...
cot(x) ≥ 1
The cotangent function decreases from ∞ to 1 in the domain (0, π/4], and again in the domain (π, 5π/4]. The solution is the union of these two intervals.
x ∈ (0, π/4] ∪ (π, 5π/4]
_____
(a, b] is interval notation for a < x ≤ b