Answer:
The remaining interior angles of this triangle are 140º and 10º
Step-by-step explanation:
The sum of the interior angles of a triangle is always 180º.
A triangle has 3 angles. In this problem, we have one of them, that i am going to call A1 = 30º.
The sum of a interior angle with it's respective exterior angle is also always 180º.
We have that one of the exterior angles is equal to 40°. So it's respective interior angle is
40º + A2 = 180º
A2 = 180º - 40º
A2 = 140º
Now we have two interior angles, and we know that the sum of the 3 interior angles is 180º. So:
A1 + A2 + A3 = 180º
A3 = 180º - A1 - A2
A3 = 180º - 30º - 140º
A3 = 180º - 170º
A3 = 10º
The simplified expression is 6+3i
Answer:
3 1/2 plus 1 1/2? if thats it then it would be 5 i guess
Step-by-step explanation:
Answer:
a) PR = 17 cm, b) QR = 6 cm
Step-by-step explanation:
∠Q=90, so PQ and QR are legs, and PR is hypotenuse.
Pythagorean theorem PQ² + QR² = PR²
a) PQ² + QR² = PR²
8² + 15² = PR²
PR² = 289
PR = 17 cm
b) PQ² + QR² = PR²
8² + QR² = 10²
64 + QR² = 100
QR² = 36
QR = 6 cm
