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lesya [120]
3 years ago
7

What is the center of a circle whose equation is x^2+y^2-12x-2y+12=0

Mathematics
2 answers:
Alexxx [7]3 years ago
8 0

Answer:

centre = (6, 1 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² - 12x - 2y + 12 = 0

Collect the x and y terms together and subtract 12 from both sides

x² - 12x + y² - 2y = - 12

To obtain the equation in standard form use completing the square

add ( half the coefficient of the x/ y term )² to both sides

x² + 2(- 6)x + 36 + y² + 2(- 1)y + 1 = - 12 + 36 + 1

(x - 6)² + (y - 1)² = 25 ← in standard form

with centre = (6, 1 ) and radius = \sqrt{25} = 5

Evgen [1.6K]3 years ago
7 0

Answer:

(6, 1)

Step-by-step explanation:

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3 0
2 years ago
A group of 100 people is divided into 2 teams with 45 people in team A and 55 people in team B.
Zepler [3.9K]
Team A) 45 people
Team B) 55 people

A)There are two ways to solve this problem, finding the number of combinations possible for Team B, or the number of combinations possible for Team A. 
Team A
It's a given that 20 mathematicians are on team A, which leavs the other 25 people for team A to be chosen from a pool of 80 (100- 20 mathletes)
80-C-25 = 80! / (25!/(80-25)!) =<span>363,413,731,121,503,794,368
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Solving using Team B
Same concept, but choosing 55 from a pool of 80 (mathletes excluded)
80-C-25 = 80! / (55!(80-55!) = 363,413,731,121,503,794,368
or 3.63 x 10^20

As you can, we get the same answer for both. 

B)
If none of the mathematicians are on team A, then we exclude the 20 and choose 45:
80-C-45 = 80! / (45!(80-45)!) = <span>5,790,061,984,745,3606,481,440
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Note that, if you solve from the perspective of Team B (80-C-35), you get the same answer</span>
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3 years ago
ANSWER FAST FOR BRAINLIEST!!!!!!!!!!!!!!!!!
Elis [28]

Answer:

i believe it is B

Step-by-step explanation:

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