Answer:
hello your question is incomplete here is the complete question
Use cylindrical coordinates Find the volume of the solid that lies within both the cylinder x^2 + y^2=16 and the sphere x^2 + y^2 + Z^2= 81
Answer : ![\frac{4 \pi }{3} [729 - 65\sqrt{65} ]](https://tex.z-dn.net/?f=%5Cfrac%7B4%20%5Cpi%20%7D%7B3%7D%20%5B729%20-%2065%5Csqrt%7B65%7D%20%5D)
Step-by-step explanation:
The given data
cylinder = x^2 + y^2 = 16
sphere = x^2 + y^2 +z^2 = 81
from the given data the solid is symmetric around the xy plane hence we will calculate half the solid volume above the plane then multiply the sesult by 2
Note : we are restricting our attention to the cylinder x^2 + y^2 = 16 and also finding the volume inside the sphere which gives bound on the z-coordinate as well
the r parameter goes from 0 to 4
ATTACHED IS THE REMAINING PART OF THE SOLUTION
showing the integration
Answer:
x=27
Step-by-step explanation:
Let's solve your equation step-by-step.
4(x−5)=3x+7
Step 1: Simplify both sides of the equation.
4(x−5)=3x+7
(4)(x)+(4)(−5)=3x+7(Distribute)
4x+−20=3x+7
4x−20=3x+7
Step 2: Subtract 3x from both sides.
4x−20−3x=3x+7−3x
x−20=7
Step 3: Add 20 to both sides.
x−20+20=7+20
x=27
Answer:
x=27
A subtraction equation is 6.88-4.96= w.
The weight of ingredients other than granola is 1.92 pounds.
6.88
- 4.96
---------
1.92