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3 years ago

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Which checkpoint in the cell cycle is affected by paclitaxel?

1 answer:

svp [43]3 years ago

5 0

CHECKPOINT M in the cell cycle is affected by paclitaxel.

Paclitaxel (PTX) is a compound that is sold under the brand name "Taxol" which is used to treat cancer. G1, G2 and M are the 3 checkpoints where all the chromosomes get attached attached to the spindle fibers. Paclitaxel inhibits the assembly and disassembly of the microtubules and prevents the separation of chromosomes during cell division.

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Vascular tissues main function is

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Answer:

The vascular tissues include xylem, which conducts water and minerals from the roots upward and throughout the plant, and phloem, which transports dissolved nutrients in all directions within the plant. The main conducting vessels of xylem are the tracheids and the vessels.

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Explanation:

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The count in a bacteria culture was 100 after 20 minutes and 2000 after 40 minutes. Assuming the count grows exponentially, What

Afina-wow [57]

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Explanation:

Let X be the number of bacteria at time t, and Xo be the initial number of bacteria

Bacteria grows exponentially, the exponential growth model is thus:

X = Xo $e^{kt}$

[<em>e</em> is the exponential sign]

k is the growth constant = growth rate

At t = 20 minutes, X = 100

At t = 40 minutes, X = 2000

Substituting that into the formula

(i) ... 100 = Xo $e^{k20}$

(ii) ... 2000 = Xo $e^{k40}$

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$\frac{2000}{100} = \frac{Xoe^{40k} } {Xoe^{20k}}$

20 = $e^{40k-20k} = e^{20k}$

<em>[Xo cancels Xo. Division of values raised to a power is done by subtracting their powers]</em>

<em>Take the natural log of both sides</em>

㏑20 = 20k

<em>[taking the ㏑ cancels the exponential]</em>

k = $\frac{ln20}{20}$

<em>We can now substitute k to solve one of the equations</em>

<em>substituting k in (ii)</em>: 2000 = Xo $e\frac{ln 20}{20}.^{40}$

2000 = Xo $e^{0.15*40}$

2000 = Xo $e^{6}$

<em>Making Xo the subject of the formula</em>

Xo = $\frac{2000}{e^{6} }$

Xo is approximately 5 cells.

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The doubling time is the time it takes for the population to double, so 5 cells become 10 cells

Since Xo = 5

Given that X = Xo $e^{kt}$

When X=10,

10 = 5 $e^{0.15t}$

<em>solving for t:</em>

$e^{0.15t} = \frac{10}{5}$

Take ln of both sides

0.15t = ln 2

t = $\frac{ln2}{0.15}$

t =4.62 minutes

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X = 5 $e^{0.15*65}$

X = 85770

WHEN WILL THE POPULATION REACH 12000

12000 = 5 $e^{0.15t}$

$e^{0.15t}$ =240

take ln of both sides

0.15t = ln 2400

t = 51.89 minutes (approximately 52 minutes)

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