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Len [333]
3 years ago
9

Find the linear equation of the plane through the point (2,4,9) and parallel to the plane x+4 y+5 z+4 =0.

Mathematics
1 answer:
storchak [24]3 years ago
4 0
Y = x + 5A linear equation (in slope-intercept form) for a line perpendicular to y = -x + 12 with a y-intercept of 5.y = 1/2x - 5Convert the equation 4x - 8y = 40 into slope-intercept form.y = -1/2x + 5A linear equation (in slope-intercept form) which is parallel to x + 2y = 12 and has a y-intercept of 5.3x - y = -5A linear equation (in standard form) which is parallel to the line containing (3, 5) and (7, 17) and has a y-intercept of 5.y = -3x + 1A linear equation (in slope-intercept form) which contains the points (10, 29) and (-2, -7).y = -5A linear equation which goes through (6, -5) and (-12, -5).x = -5A linear equation which is perpendicular to y = 12 and goes through (-5, 5).y = 5A linear equation which is parallel to y = 12 and goes through (-5, 5).y = -x + 5A linear equation (in slope-intercept form) which is perpendicular to y = x and goes through (3, 2).y = -5xA linear equation (in slope-intercept form) which goes through the origin and (1, -5).x = 2A linear equation which has undefined slope and goes through (2, 3).y = 3A linear equation which has a slope of 0 and goes through (2, 3).2x + y = -9A linear equation (in standard form) for a line with slope of -2 and goes through point (-1, -7).3x +2y = 1A linear equation (in standard form) for a line which is parallel to 3x + 2y = 10 and goes through (3, -4).y + 4 = 3/2 (x - 3)A linear equation (in point-slope form) for a line which is perpendicular to y = -2/3 x + 9 and goes through (3, -4).y - 8 = -0.2(x + 10)<span>The table represents a linear equation.
Which equation shows how (-10, 8) can be used to write the equation of this line in point-slope form?</span>
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Parallel is the answer
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3 years ago
It takes you 5 hours to complete a 375-kilometer trip. What was your average speed on this trip?
morpeh [17]

Answer:

75

Step-by-step explanation:

V=S/T(the formula)

V= 375/5

V=75

4 0
3 years ago
Read 2 more answers
Q1: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.
marin [14]

Answer:

C. hyperbola; 9x^2-25y^2-250y-850=0

Step-by-step explanation:

The given conic has equation:

9x^2-25y^2=225

Divide through by 225.

\frac{9x^2}{225}-\frac{25y^2}{225}=\frac{225}{225}

\frac{x^2}{25}-\frac{y^2}{9}=1

This is a hyperbola centered at the origin.

The hyperbola has been translated from the origin to (0,5).

The translated hyperbola will have equation;

\frac{(x-0)^2}{25}-\frac{(y-5)^2}{9}=1

Multiply through by 225.

9(x-0)^2-25(y-5)^2=225

Expand

9x^2-25(y^2-10y+25)=225

9x^2-25y^2+250y-625=225

Rewrite in general form;

9x^2-25y^2+250y-625-225=0

9x^2-25y^2+250y-850=0

3 0
3 years ago
A sphere with a diameter of 30 inches is placed in a cube. The sphere touches the lateral faces
Nina [5.8K]

Answer:

a) 30 inches × 30 inches × 30 inches

b) 27,000 inches³

c) 14,130 inches³

d) 12,870 inches³

Step-by-step explanation:

Edge of the cube = diameter = 30 inches

Volume of cube = s³

30³ = 27000 inches³

Radius = 30/2 = 15

Volume of sphere:

(4/3) × 3.15 × 15³

14130 inches³

Difference:

27000 - 14130

12870 inches³

5 0
3 years ago
In a certain sequence of numbers, each term after the first is found by doubling and then adding $3$ to the previous term. If th
eimsori [14]
Given a_7=125 you can find a_6:

a_6= \frac{125-3}{2} =61
 a_5= \frac{61-3}{2} =29 \\ a_4= \frac{29-3}{2}=13 \\ a_3= \frac{13-3}{2} =5 \\ a_2= \frac{5-3}{2} =1 \\ a_1= \frac{1-3}{2}=-1
Answer: -1
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3 years ago
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