Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,


![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)



meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
Equation 1 would be: 3a+2C
Equation 2 would be: 5a+3C
The answer for this question is 36
Answer:
x^2 – 3xy + 2y^2
Step-by-step explanation:
Factor the following:
x^2 - 3 x y + 2 y^2
Hint: | Factor the quadratic x^2 - 3 x y + 2 y^2.
The factors of 2 that sum to -3 are -1 and -2. So, x^2 - 3 x y + 2 y^2 = (x - 1 y) (x - 2 y):
Answer: (x - y) (x - 2 y)
"the following" of what? I think you are missing the list