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Helen [10]
3 years ago
13

What steps do I do to answer this

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0
Your equation is: 5h + 4 = 10h + 8

First subtract 5h from both sides:(So that variable terms stays in one side only)

=> 5h + 4 -5h = 10h + 8 -5h

=> 4 = 5h + 8

Now subtract 8 from both sides:(So constant term stays in the opposite side of variable terms)

=> 4 - 8 = 5h + 8 - 8

=> -4 = 5h

Now divide both sides by 5:(division by coefficient of variable)

=> -4/5 = 5h/5

=> -4/5 = h

=> h = -4/5 = -0.8


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Please help due today
umka21 [38]

Answer:

y=2 x=3 i think

Step-by-step explanation:

2y+3=y+5

y=5-3

y=2

4x-3=4y+1

4x-3=4×2+1

4x-3=9

4x=9+3

4x=12

x=12/4

×=3

3 0
2 years ago
Find the surface area of the figure shown,<br> correct to 2 decimal places.
agasfer [191]

Answer:

230.73m^2

Step-by-step explanation:

A=2a^2+4ah=2*4^2+4*4*4=96m^2 (square prism)

A=2\pi rh+2\pi r^2=2*\pi *4*9+2*\pi *4^2 = 326.73m^(cylinder)

326.73-96=230.73m^2 (\frac{3}{4} cylinder)

7 0
2 years ago
Use the Law of Cosines to find the missing angle. In triangle FGH, HF = 16 ft, FG = 23 ft, and m∠F = 52°. Find the measure of f.
ivolga24 [154]
F = 18 ft.

The law of cosines states 
c² = a² + b² - 2ab cos C

Using our information, we have 
c² = 23² + 16² - 2(23)(16)cos 52
c² = 529 + 256 - 736cos 52
c² = 785 - 736cos 52
c² = 331.8732

Taking the square root of both sides, we have
c = √331.8732 = 18.22 ≈ 18
5 0
3 years ago
PLEASE PLEASE PLEASE HELP ME!!!!! PLEASE PLEASE ILL GIVE POINTS, BRAINLY, AND THANKS
Murljashka [212]

Composing function is applying one function to the result of another and an arithmetic operation is when you add, subtract, multiply, or divide two functions.

8 0
2 years ago
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
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