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Mashcka [7]
2 years ago
11

What is the equation of the translated function, g(x), if f(x) = x2? g(x) = (x 5)2 2 g(x) = (x 2)2 5 g(x) = (x – 2)2 5 g(x) = (x

– 5)2 2
Mathematics
2 answers:
Alex2 years ago
7 0

Answer:

the equation of the translated function is,

g(x) = (x – 5)^2 + 2

Step-by-step explanation:

got it right on edge

Oksana_A [137]2 years ago
5 0

Answer:

13.54

Step-by-step explanation:

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Consider the differential equation:
Wewaii [24]

(a) Take the Laplace transform of both sides:

2y''(t)+ty'(t)-2y(t)=14

\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s

where the transform of ty'(t) comes from

L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)

This yields the linear ODE,

-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s

Divides both sides by -s:

Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}

Find the integrating factor:

\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C

Multiply both sides of the ODE by e^{3\ln|s|-s^2}=s^3e^{-s^2}:

s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}

The left side condenses into the derivative of a product:

\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}

Integrate both sides and solve for Y(s):

s^3e^{-s^2}Y(s)=7e^{-s^2}+C

Y(s)=\dfrac{7+Ce^{s^2}}{s^3}

(b) Taking the inverse transform of both sides gives

y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that \frac{7t^2}2 is one solution to the original ODE.

y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7

Substitute these into the ODE to see everything checks out:

2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14

5 0
3 years ago
What is 8 minus the quotient of 15 and y
DerKrebs [107]
You would end up with an equation of 8 - y/15.
6 0
3 years ago
The scatter plot shows which type of correlation?
andre [41]

Answer:

negative correlation

Step-by-step explanation:

because it starts from the y axis

8 0
3 years ago
Find the area of a circle with a diameter of 1.5 m.<br><br><br> 4.71 m2<br><br><br> 1.77 m2
nikdorinn [45]
I hope this helps you



radius=diameter/2



radius=1,5/2


radius=0,75


Area=pi. r^2


Area=3,14. (0,75)^2


Area=1,76
7 0
3 years ago
Replace ? with an expression that will make the equation valid.
AlexFokin [52]

Answer:

4x³

Step-by-step explanation:

d/dx ln(x⁴ + 7) = 1/(x⁴ + 7) × _?

To obtain the missing expression, let us simplify d/dx ln(x⁴ + 7). This can be obtained as follow:

Let y = ln (x⁴ + 7)

Let u = (x⁴ + 7)

Therefore,

ln(x⁴ + 7) = ln u

Thus,

y = ln u

dy/du = 1/u

Next, we shall determine du/dx. This is illustrated below:

u = (x⁴ + 7)

du/dx = 4x³

Finally, we shall determine dy/dx of ln (x⁴ + 7) as follow:

dy/dx = dy/du × du/dx

dy/du = 1/u

du/dx = 4x³

dy/dx = 1/u × 4x³

But:

u = (x⁴ + 7)

Therefore,

dy/dx = 1/(x⁴ + 7) × 4x³

Thus, the missing expression is 4x³

6 0
3 years ago
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