First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
Answer:
-320 i guess
Step-by-step explanation:
51*-2*3-21+7=-320
Answer:
i cant sseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Step-by-step explanation:
the picture
Answer: No, the answer is 29, this is false.
Step-by-step explanation: 63-x=34
subtract 63 from both sides
34-63= -29
-x=-29
divide both sides by the negative and you get 29
plug in 29 for x, 63-29=34
The correct answer for this problem is it has infinity solutions. Both equations equal up to t=5 -1/2
