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babymother [125]
4 years ago
14

Consider the following pair of equations:

Mathematics
1 answer:
lbvjy [14]4 years ago
3 0
-x-y=-5
-x+y=1

adding up the equations gives;
-2x=-4
x=2

replacing in the first equation;
-2-y=-5
-2+5=y
y=3
They would intersect at (2,3)
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damaskus [11]

Answer: 3

Step-by-step explanation:

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12C - 14C = - 10 + 4

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C = <u>- 6</u>

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C = 3

   

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garik1379 [7]

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5 0
3 years ago
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3 years ago
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3 years ago
Find the equation of the axis of symmetry of the graph of y = (x + 3)^2 - 5
Temka [501]
Equation of the parabola: y = ax^2 + bx + c. Find a, b, and c.
x of axis of symmetry:
x
=
−
b
2
a
=
3
-> b = -6a
Writing that the graph passing at point (1, 0) and point (4, -3):
(1) 0 = a + b + c -> c = - a - b = - a + 6a = 5a
(2) -3 = 16a + 4b + c --> -3 = 16a - 24a + 5a = -3a --> a = 1
b = -6a = -6; and c = 5a = 5
y
=
x
2
−
6
x
+
5

Check with x = 1: -> y = 1 - 6 + 5 = 0. OK
3 0
4 years ago
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