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Bess [88]
3 years ago
5

HEEEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Bingel [31]3 years ago
8 0
2(2/5+1/5)=2•3/5=6/5=1 1/5
Answer is C
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Convert 68°C to degrees Fahrenheit. If necessary, round your answer to the nearest tenth of a degree
Karolina [17]

Answer: 154.4 Fahrenheit

Step-by-step explanation: 68°C = ( 68× 9 / 5 + 32 ) = 154.4°F

6 0
3 years ago
Please explain if you can ​
Sonja [21]

Using it's concept, the probabilities are given as follows:

19. A. 1/3.

20. F. 1/6.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are 1 + 1 + 3 + 4 + 3 = 12 papers. 4 have a score of 6, hence, in item 19, the probability is:

p = 4/12 = 1/3.

Which means that option A is correct.

2 papers have a score greater than 12, hence the probability in item 20 is given by:

p = 2/12 = 1/6.

Which means that option F is correct.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

8 0
2 years ago
What is the value of x in the equation 8x-2y=48, when y=4
Oksanka [162]
8x - 2y = 48,  y =4

8x - 2(4) = 48
8x - 8 = 48
8x = 48+8
8x  = 56
x = 56/8 = 7

x = 7
8 0
3 years ago
Read 2 more answers
Given f(x) = (lnx)^3 find the line tangent to f at x = 3
kirill [66]
Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

6 0
1 year ago
Complete the table below.<br> HeLPP ILL GIVE BRAINLIEST!
makkiz [27]
Here...see the attachment

6 0
3 years ago
Read 2 more answers
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