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9966 [12]
3 years ago
12

Solve when x ∈ {-2, 0, 2} and y ∈ {-3, -1, 0, 3} y=1-x^2

Mathematics
1 answer:
natka813 [3]3 years ago
5 0

Answer:

(-2,-3) and (2,-3).

Step-by-step explanation:

It is given that x ∈ {-2, 0, 2} and y ∈ {-3, -1, 0, 3} .

The given equation is

y=1-x^2

At x=-2,

y=1-(-2)^2=1-4=-3\in y

At x=0,

y=1-(0)^2=1-0=1\notin y

At x=2,

y=1-(2)^2=1-4=-3\in y

Therefore, the solution of given equation are (-2,-3) and (2,-3).

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True

Step-by-step explanation:

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Twelve students tried out for the cheerleading squad. Four students were selected. What is the ratio of students selected to tho
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4:12

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6 0
3 years ago
PLEASE I NEED HELP !!!!!!
kogti [31]
I’m pretty sure it’s B. -3/8x - 1/4 :).
5 0
3 years ago
What two ratios are equivalent to 10:18
Whitepunk [10]
10 : 18          2 into 10 is 5, 2 into 18 is 9.

5 : 9.

You can also choose to multiply 10 : 18 by 2.

2*10 : 2*18

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6 0
4 years ago
Read 2 more answers
Find the perimeter A(2,2),(6,-2),(5,1)​
Verizon [17]

Answer:

4√2 + 2√10

Step-by-step explanation:

Finding the perimeter here involves finding three point-to-point distances and then adding them up.

From (2, 2) to (6, -2) we have a change in x of 4 and a change in y of -4.  We use the Pythagorean Theorem to determine the distance, which is the hypotenuse of a right triangle:

√( [4]² + [-4]² ) = 4√2.  This is the length of the side connecting (2, 2) and (6, -2).

From (6, -2) to (5, 1), the distance is √( [-1]² + 3² ), or √10.

From (5, 1) to (2, 2), the distance is √( [-3]² + 1² ), or √10.

The perimeter is the sum of these three distances and is:

4√2 + √10 + √10, or   4√2 + 2√10

7 0
3 years ago
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