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3 years ago

Given right triangle ABC with altitude BD drawn to hypotenuse AC. If

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

7 0

The length will be 3 because of the altitude

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reflect a circle about a line L through its center, then rotate it through 40◦ counterclockwise, and then reflect it once more a

Neporo4naja [7]

Answer:

The answer is provided in the attachments as Picture.

Step-by-step explanation:

We take a circle with a line L passing through its center and mark a point P initially on the circle.

No, we perform all the mentioned operations on the circle and note the change through the change in position of P.

The whole procedure is attached as the PNG in the answer.

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3 years ago

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3 years ago

{6y^3+2y^2}{10y^2}= 10y 2 6y 3 +2y 2 =start fraction, 6, y, cubed, plus, 2, y, squared, divided by, 10, y, squared, end fracti

malfutka [58]

Answer:

y=0

Step-by-step explanation:

Definition:An expression is undefined at the value(s) at which the denominator equals zero.

We are to determine the value of y that makes the expression undefined.

$\dfrac{6y^3+2y^2}{10y^2}$

We equate the denominator to zero and solve for y.

$10y^2=0\\y^2=0\\y=0$

Therefore, at y=0, the given expression is undefined.

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3 years ago

Which number, when placed in the box, will make the equation true? _^2 =square root of 64

velikii [3]

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3 years ago

Read 2 more answers

Given: m∠LON=77 ° m∠LOM=9x+44 ° m∠MON=6x+3 ° Find ∠MON

NISA [10]

Answer:

$m\angle MON=15^o$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

$m\angle LON=m\angle LOM+m\angle MON$ ---> by addition angle postulate

substitute the given values

$77^o=(9x+44)^o+(6x+3)^o$

solve for x

$77=(15x+47)$

$15x=77-47$

$15x=30\\x=2$

Find the measure of angle MON

$m\angle MON=(6x+3)^o$

substitute the value of x

$m\angle MON=(6(2)+3)=15^o$

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3 years ago