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DiKsa [7]
3 years ago
12

Two cards are selected from a standard deck of 52 playing cards. The first is replaced before the second card is selected. Find

the probability of selecting a heart and then selecting a nine. The probability of selecting a heart and then selecting a nine is ____.
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
5 0
2 cards selected from a standard 52 card deck

P(1st card is a heart) = 13/52....because there are 13 hearts in a deck of cards
the card is replaced
P(2nd card is a 9) = 4/52 which reduces to 1/13

so the probability of both events happening is : 13/52 * 1/13 = 1/52 <=     
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A surveyor is conducting measures to see how wide a road is
drek231 [11]

Answer:

D) 45 ft

Step-by-step explanation:

The two triangles are shown below.

Given:

BC = 60 ft, CD = 24 ft and DE = 18 ft.

Since, the two triangles are similar, their corresponding sides are in proportion.

So, \frac{AB}{DE}=\frac{BC}{CD}=\frac{AC}{CE}

Now, consider the proportion of sides,

\frac{AB}{DE}=\frac{BC}{CD}\\AB=\frac{BC}{CD}\times DE\\AB=\frac{60}{24}\times 18\\AB=\frac{60\times 18}{24}=45\ ft

Therefore, the distance between A and B is 45 ft.

8 0
3 years ago
Someone please help
kkurt [141]
First, make y negative

y=-x-1

From there, you would go down 1 and right 1

3 points you could choose are (0,-1), (-2,1), and (-3,2)
7 0
3 years ago
I will give 10 pt to who ever answer the question
kap26 [50]
OK, because it is asking you to subtract a (negative) number and two negatives make a positive, the question would be -56 + 27.07 = ? with some simple addition, the answer would be <span>-28.93.

I hope this helps :)</span>
3 0
3 years ago
Read 2 more answers
6(m-3)÷4)-5<br>greater than<br>2(4m-8)+12
ziro4ka [17]
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3 0
4 years ago
Find the least common multiple of: 12x^3y^2 and 15x^2y^5
allochka39001 [22]

Answer: 60x^3y^5

Step-by-step explanation:

Least Common Multiple :The least positive number that is a multiple of two or more numbers.

To find : The least common multiple of: 12x^3y^2 and 15x^2y^5.

Since, 12x^3y^2=2\times2\times3\times x^3y^2

15x^2y^5=3\times5\times x^2y^5

The least common multiple of: 12x^3y^2 and 15x^2y^5. = 2\times2\times3\times5\times x^3y^5=60x^3y^5 [take highest power of x and y ]

Hence, the least common multiple of: 12x^3y^2 and 15x^2y^5. = 60x^3y^5

3 0
3 years ago
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