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2 years ago

14

Do I multiply all together, please

2 answers:

LiRa [457]2 years ago

7 0

Answer:

40 m

Step-by-step explanation:

A= b(h)

A= 8(5)

A= 40 m

antiseptic1488 [7]2 years ago

3 0

Answer:

It is a parallelogram and the area is 40.

Step-by-step explanation:

The area of a parallelogram is a=bh.

The base is 8 and the height is 5. All you do is times 8 and 5 to get 40.

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A − 7 = 3 (b+2) pls answer soon

Alexeev081 [22]

I believe the answer is....

For solving for a

a-7= 3(b+2) ———> distribute 3(b+2)
a-7= 3b+6 ———-> add 7 on both sides

a-7= 3b+6
a+7= 3b +7 ———-> the 7’s cancel out so you’re left with....

a = 3b + 13 (That’s your answer)

Hope that helped :3

8 0

3 years ago

Help please . What does ad equal

tangare [24]

Answer:

AD also equal 14

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

13 - 8m = 21<br> por favor ayuda

Ulleksa [173]

Si estás tratando a encontrar M este es
13-8m=21
8m=8
M=1

6 0

3 years ago

Plz get me the correct answer or u will be reported. 15 points for correct answer. Thx.

allochka39001 [22]

Answer:

D

Step-by-step explanation:

correct answer, thanks for 15 pts

7 0

2 years ago

Read 2 more answers

Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced

Sati [7]

Answer:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

Step-by-step explanation:

$\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls}$ , $(denoted \:W_1, W_2, \:and\: W_3)$

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

The tree diagram of this event is also attached.

6 0

3 years ago