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torisob [31]
2 years ago
8

Solving the formula P = 2L + 2W for W is NOT equivalent to which equation?

Mathematics
1 answer:
emmasim [6.3K]2 years ago
7 0

Answer:

3rd one

Step-by-step explanation:

2l + 2w = P

2w = P - 2l

w = P - 2l / 2

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The perimeter of the triangle shown are equal. Find the side lengths of each triangle.
Lunna [17]

Good morning ☕️

___________________

Step-by-step explanation:

Let p1 be the perimeter of triangle ABC

p2 be the perimeter of triangle PQR

p1=(2x+4)+(2x+3)+(2x) = 6x+7

p2=(2x)+(2x)+(3x+1) = 7x+1

p1=p2 ⇔ 6x+7=7x+1 ⇔ 7x-6x=7-1 ⇔x=6

Then :

AC=2(6)=12

AB=2(6)+4=16

BC=2(6)+3=15

PQ=12

QR=12

PR=3(6)+1=19.

_____

:)

6 0
3 years ago
Read 2 more answers
What's the answer to 5 1/3-5/8=
nasty-shy [4]

step-by-step

5 1/3-5/8

16/3-5/8

113/24

4 17/24

the answer was 4 17/24 if for  decimal was 4.708333

and I hope that helps you

7 0
2 years ago
The population of gray wolves in Wisconsin increased from 570 in 2007 to 660 in 2014. Find the percent increase in the wolf popu
melamori03 [73]

Answer:

15.78947% increase

Step-by-step explanation:

First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number

Then:  divide the increase by the original number and multiply the answer by 100.

% increase = Increase ÷ Original Number × 100

7 0
2 years ago
Is 20% greater than 0.02
Ket [755]
Yep it is greater. Hope this helps
6 0
3 years ago
Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
2 years ago
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