Answer: Margin of Error for the given CI is 0.08
Step-by-step explanation:
Given the data in the question;
it is a symmetric class interval hence, sample proportion p = (0.50 + 0.66) / 2
p = 1.16 / 2
sample proportion p = 0.58
Margin of Error E will be;
E = 1/2 × length of Confidence interval
Margin of Error E = 1/2 × ( 0.66 - 0.5)
Margin of Error E = 1/2 × 0.16
Margin of Error E = 0.08
Therefore; Margin of Error for the given CI is 0.08
<span>If One full revolution is 8 seconds when the dent is 6.5 inches above floor and the dent at the bottom is 0.5 inches above floor, the answer will be half a revolution or 4 seconds when the dent is at the bottom..</span>
Answer:
![P(A \cup B) =0.45](https://tex.z-dn.net/?f=P%28A%20%5Ccup%20B%29%20%3D0.45)
Step-by-step explanation:
From the question we are told that
Consumers seen the soap ![P_A=40\% =0.40](https://tex.z-dn.net/?f=P_A%3D40%5C%25%20%3D0.40)
Consumers used the soap ![P_B=20\% =0.2](https://tex.z-dn.net/?f=P_B%3D20%5C%25%20%3D0.2)
Consumers seen/tried the soap ![P_x=15\% =0.15](https://tex.z-dn.net/?f=P_x%3D15%5C%25%20%3D0.15)
Generally the probability that consumers have seen and tried the soap is
![P(A \cup B=P(A)+P(B)-P(A \cap B](https://tex.z-dn.net/?f=P%28A%20%5Ccup%20B%3DP%28A%29%2BP%28B%29-P%28A%20%5Ccap%20B)
![P(A \cup B=0.4+0.2-0.15](https://tex.z-dn.net/?f=P%28A%20%5Ccup%20B%3D0.4%2B0.2-0.15)
![P(A \cup B) =0.45](https://tex.z-dn.net/?f=P%28A%20%5Ccup%20B%29%20%3D0.45)
The anwser is zero
You see, 5 to the exponent of 0 is 5 0 times then if you multiply 5 to the explnent of 1 by zero the anwser is zero because zero times 5 is zero