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vodomira [7]
3 years ago
13

Can somebody help me with number 7?

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0

I believe that the only rational one would be the first one as it's repeating.

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Rita started the day with r apps then she deleted 5 apps and still had twice as many apps as Cora has .write and an equation tha
Elodia [21]

Answer:

r - 5 = 2c

r = 75

Step-by-step explanation:

To write an equation for the problem, we first need do declare the value of the number of apps cora has.

Let c = Cora's apps

r - 5 = 2c

r - 5 is used to indicate that Rita deleted 5 apps.

2c is used to represent the twice the number of apps Cora has.

Now you said that Cora had 35 apps.

Let's plug that into the equation.

r - 5 = 2c

r - 5 = 2(35)

r - 5 = 70

Now we transpose the -5 to the other side to leave r.

r = 70 + 5

r = 75

So if Cora has 35 apps, then Rita will have 75 apps.

3 0
3 years ago
AYOOOOOOOOOOOOOO I NEED HELP!!!!!!!!!!
ArbitrLikvidat [17]

Answer:

The Slope is 1/4

Step-by-step explanation:

:))))

5 0
3 years ago
A baseball team has home games on Friday and Sunday. The two games together earn ​$3532.50 for the team. Friday​'s game generate
Semmy [17]
First you would divide $3532.50 by 2 which would equal $1766.25.
The you would add $225.75 to $1766.25 which equals $1982.
The Friday had $1540.50 taken in & the Sunday game had $1982 taken in.

5 0
4 years ago
Please help me with this!! (20 points)
alexandr402 [8]

Answer:

BC, BD

Step-by-step explanation

If right please brainly

5 0
4 years ago
Find the local max and min values of f(x)=x^2/x-1 using both first and second derivative tests
uranmaximum [27]
Hmm, the 2nd derivitve is good for finding concavity

let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient

so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x

so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points

f'(-1)>0
f'(1.5)<0
f'(3)>0

so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)


we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense




local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))
6 0
4 years ago
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