B-4/6 how do I solve this? It's hard
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Using Pythagoras theorem, the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.
Let distance from the wall to the foot of the ladder is 'x' feet and the height of the top of the ladder is 'y' feet.
Pythagoras theorem, --->(1)
Given, at x=3
Put x=3 in Pythagoras theorem equation (1)
= 135
y = 11.61
Derive equation (1) w.r.t to 't'
---->(2)
substitute the value of 'x', 'dx/dt' and 'y' in equation (2), we get the fast of the top of the ladder moving down when the foot of the ladder is 3 feet from the wall
12 + 23.22 = 0
Hence, using Pythagoras theorem the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.
Learn more about Pythagoras theorem here
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