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Citrus2011 [14]
3 years ago
11

Julie travels 3 times as fast as Bill. Traveling in opposite directions, they are 190 miles apart after 2.5 hours. Find their ra

tes of travel.
Mathematics
1 answer:
Mkey [24]3 years ago
6 0

Answer:

Step-by-step explanation:

Let b

Bill's rate of travel = x

Let Julie's rate of travel = 3x

The time each travels is 2.5 hours

Together they travel a distance of 190 miles

d = r*t

Bill's distance covered is r * t = 2.5x

Julie's distance travel is 2.5 * 3x = 7.5x

The total distance = Bill + Julie

2.5x + 7.5x = 190

10x = 190

x = 190/10

x = 19

Bill's distance = 2.5 * 19 = 47.5

Julie's distance = 19 * 7.5 = 142.5

Rate = distance / time

Bill's rate = 47.5 / 2.5 = 19 miles per hour.

Julie's rate = 142.5/2.5 = 57 miles per hour

Is there an easier way?

You should notice that Bill's rate is just x which is 19 miles / hour

You can also notice that Julie is going 3 times as fast or 19*3 = 57

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Hello!
The Answer Is 28.14
Because (42x33)/100=13.86
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3 years ago
2) Brian purchased pens for 75 cents each and pencils for 40 cents each he bought total of 22 writing utensils for $11.95. How m
d1i1m1o1n [39]

Answer:

13 pencils.

Step-by-step explanation:

Let x be the pens and y be the pencils

Given:

Brian purchased pens for 75 cents each and pencils for 40 cents each he bought total of 22 writing utensils for $11.95.

Total pens and pencils is 22

So, x+y=22----------------(1)

And he bought all utensils for $11.95. and each pen for 75 cents and pencils for 40 cents.

0.75x+0.40y=11.95------------(2)

solve equation 1 and equation 2 for x and y.

From equation 1.

x+y=22

y=22-x----------------(3)

put y value in equation 2.

0.75x+0.4(22-x)=11.95

0.75x+0.4\times 22-0.4x=11.95

0.75x+8.8-0.4x=11.95

0.75x-0.4x=11.95-8.8

0.35x=3.15

x=\frac{3.15}{0.35}

x=9

Now substitute x value in equation 3.

y=22-9

y=13

So, he buy 13 pencils.

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Find the quotient. 8,489÷9
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I need help on my homework
soldi70 [24.7K]

Answer:

\displaystyle m\angle AED=32.5^\circ

Step-by-step explanation:

<u>Angles in a Circle</u>

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.

Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:

\displaystyle m\angle AED=\frac{AD-BC}{2}

\displaystyle m\angle AED=\frac{113^\circ-48^\circ}{2}=\frac{65^\circ}{2}

\displaystyle m\angle AED=32.5^\circ

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