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Delvig [45]
3 years ago
9

Highland missed 16 out of 78 points on his last test. What letter grade did he earn?

Mathematics
2 answers:
Papessa [141]3 years ago
8 0

The letter grade he got was around a C or a low B.


Hitman42 [59]3 years ago
3 0
Divide 16/78 points and that will be the percent and based on your school system it will vary. 16/78= 20% roughly do he failed
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6 0
3 years ago
Evaluate 48/6-10/3 please and thank you :)))
vodomira [7]

Answer:

14/3

Step-by-step explanation:

Simplify the following:

48/6 - 10/3

Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.

The gcd of 48 and 6 is 6, so 48/6 = (6×8)/(6×1) = 6/6×8 = 8:

8 - 10/3

Hint: | Put the fractions in 8 - 10/3 over a common denominator.

Put 8 - 10/3 over the common denominator 3. 8 - 10/3 = (3×8)/3 - 10/3:

(3×8)/3 - 10/3

Hint: | Multiply 3 and 8 together.

3×8 = 24:

24/3 - 10/3

Hint: | Subtract the fractions over a common denominator to a single fraction.

24/3 - 10/3 = (24 - 10)/3:

(24 - 10)/3

Hint: | Subtract 10 from 24.

| 2 | 4

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| 1 | 4:

Answer:  14/3

5 0
3 years ago
If cosθ=2/3 find cscθ using identities. This is in quad. 1.
laiz [17]

Step-by-step explanation:

  • cos θ = 2/3

\quad \twoheadrightarrow\sf {cos \; \theta = \dfrac{Base}{Hypotenuse} } \\

Hence, base = 2 units and hypotenuse = 3 units.

\quad \twoheadrightarrow\sf { H^2 = B^2 + P^2} \\

\quad \twoheadrightarrow\sf { P^2 = H^2 - B^2} \\

\quad \twoheadrightarrow\sf { P^2 = (3)^2 - (2)^2} \\

\quad \twoheadrightarrow\sf { P^2 = 9- 4} \\

\quad \twoheadrightarrow\bf { P = \sqrt{5}} \\

Now, we know that :

\quad \twoheadrightarrow\sf {cosec \; \theta = \dfrac{Hypotenuse}{Perpendicular} } \\

\quad \twoheadrightarrow\bf{cosec \; \theta = \dfrac{3}{\sqrt{5}} } \\

Therefore, the required answer is 3/√5.

4 0
2 years ago
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
PLEASE HELP ASAP PLEASE ANSWER CORRECTLY WILL GET BRAINLIEST
Xelga [282]

Answer:

True

Step-by-step explanation:

Each x input has 1 y output

5 0
3 years ago
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