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Lina20 [59]
4 years ago
12

If I'm trying to get polynomials in standard form.

Mathematics
1 answer:
UNO [17]4 years ago
3 0
The polynomial that would be in standard form are A and B because the exponents of the variable are decreasing.

A. 7x² - 45x + 19 ⇒ Yes
B. -8x² - 34x + 12 ⇒ Yes
C. 46 - 5x ⇒ No
    -5x + 46
D. 34 - 4x ⇒ No
    -4x + 34
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The answer would be B
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Which of the following are exterior angles? Check all that apply.
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4 years ago
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Let f (x)=1/x and g (x)=x^2+5x. A. Find (f×g)(x). B. Find the domain and range of (f×g)(x).
Ira Lisetskai [31]

we are given

f(x)=\frac{1}{x}

g(x)=x^2+5x

(A)

(f×g)(x)=f(x)*g(x)

now, we can plug it

(fXg)(x)=\frac{1}{x} (x^2+5x)

we can simplify it

(fXg)(x)=\frac{1}{x} (x(x+5))

(fXg)(x)=x+5

(B)

Domain:

Firstly, we will find domain  of f(x) , g(x) and (fxg)(x)

and then we can find common domain

Domain of f(x):

f(x)=\frac{1}{x}

we know that f(x) is undefined at x=0

so, domain will be

(-\infty,0)∪(0,\infty)

Domain of g(x):

g(x)=x^2+5x

Since, it is polynomial

so, it is defined for all real values of x

now, we can find common domain

so, domain will be

(-\infty,0)∪(0,\infty)..............Answer

Range:

Firstly, we will find range of f(x) , g(x) and (fxg)(x)

and then we can find common range

Range of f(x):

f(x)=\frac{1}{x}

we know that range is all possible values of y for which x is defined

since, horizontal asymptote will be at y=0

so, range is

(-\infty,0)∪(0,\infty)

Range of g(x):

g(x)=x^2+5x

Since, it is quadratic equation

so, its range will be

[-6.25,\infty)

now, we can find common range

so, range will be

(-6.25,0)∪(0,\infty).............Answer

6 0
3 years ago
Mr Prothero places £3003 into a
mamaluj [8]

Answer:

£3,543.54

Step-by-step explanation:

Amount after 2 years = Principal + interest

Get the interest

Interest = PRT/100

Interest = 3003 * 9 * 2/100

Interest = 3003 * 18/100

Interest  = 30.03 * 18

Interest  = 540.54

Amount after 2 years = 3003 + 540.54

Amount after 2 years = £3,543.54

6 0
3 years ago
Solve the equation.<br> 8<img src="https://tex.z-dn.net/?f=g%5E%7B3%7D" id="TexFormula1" title="g^{3}" alt="g^{3}" align="absmid
vlabodo [156]

Answer:

g = 0 or g = -1/2

Step-by-step explanation:

Solve for g:

8 g^3 - 2 g^2 = 2 g^3 - 5 g^2

Subtract 2 g^3 - 5 g^2 from both sides:

6 g^3 + 3 g^2 = 0

Factor g^2 and constant terms from the left hand side:

3 g^2 (2 g + 1) = 0

Divide both sides by 3:

g^2 (2 g + 1) = 0

Split into two equations:

g^2 = 0 or 2 g + 1 = 0

Take the square root of both sides:

g = 0 or 2 g + 1 = 0

Subtract 1 from both sides:

g = 0 or 2 g = -1

Divide both sides by 2:

Answer: g = 0 or g = -1/2

5 0
3 years ago
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