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cricket20 [7]
3 years ago
15

A produce dealer in Florida ships oranges, grapefruits, and avocados to New York by truck. Each truckload consists of 100 crates

, of which at least 20 crates must be oranges, at least 10 crates must be grapefruits, at least 30 crates must be avocados, and there must be at least as many crates of oranges as grapefruits. The profit per crate is $5 for oranges, $6 for grapefruits, and $4 for avocados. How many crates of each type should be shipped to maximize the profit?
Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0

Answer:

To maximize the profit, 35 crates of oranges, 35 crates of grapefruits and 30 crates of avocados should be shipped

Step-by-step explanation:

Maximum number of crates in each truckload = 100

Least number of crates that must be oranges = 20

Least number of crates that must be grapefruits = 10

Least number of crates that must be avocados = 30

Since the maximum number of crates in each truckload is 100 and there must be at least as many crates of oranges as grapefruits, to maximize profit, the least number of crates of oranges must be 35, the least number of crates of grapefruits must also be 35 and the least number of crates of avocados must be 30.

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ValentinkaMS [17]

Answer:

A maximum of 43 students and 11 teachers can go to the trip.

Step-by-step explanation:

Since a group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students, and the bus can hold a maximum of 54 teachers and students, to determine the possible numbers of teachers and students who can go on the trip, the following calculation must be performed:

4 + 1 = 5

54/5 = X

10.8 = X

10 x 4 = 40

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4 - 1 = 3

Therefore, a maximum of 43 students and 11 teachers can go to the trip.

8 0
2 years ago
Find the value of x in the figure
Lemur [1.5K]
X= 100°
180° - 57° = 123
x + 23°= 123°
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Use Newton's method to find all solutions of the equation correct to six decimal places. (Enter your answers as a comma-separate
Nata [24]

Answer:

  x ≈ {0.653059729092, 3.75570086464}

Step-by-step explanation:

A graphing calculator can tell you the roots of ...

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are near 0.653 and 3.756. These values are sufficiently close that Newton's method iteration can find solutions to full calculator precision in a few iterations.

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elena-s [515]

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So the initial value of the business computer is $20,000. It depreciates by 15% per year. This is exponential decay. The standard function for exponential decay is:

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It would fall between 6 and 7.
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