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Dmitry [639]
3 years ago
11

Find the magnitude of the vector 3i +4j​

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0

Answer:

5

Step-by-step explanation:

magnitude of the vector

=√(3²+4²)

=√25

=5

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Step-by-step explanation:

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STatiana [176]

Answer:

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4 0
2 years ago
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Particle 1 of charge q1 �� ��5.00q and particle 2 of charge q2 �� ��2.00q are fixed to an x axis. (a) as a multiple of distance
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<span>Assuming that the particle is the 3rd particle, we know that it’s location must be beyond q2; it cannot be between q1 and q2 since both fields point the similar way in the between region (due to attraction). Choosing an arbitrary value of 1 for L, we get </span>

<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>

Rearranging to calculate for d:

<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
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<span>
We pick the value that is > q2 hence,</span>

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<span>d = 2.72*L</span>

3 0
3 years ago
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