Answer:
p^3 / q^12
Step-by-step explanation:
p^6 q^4
------------------
p^3 q^16
We know a^b / a^c = a^(b-c)
First with variable p
p^6 / p ^3 = p^(6-3) = p^3
Then with variable q
q^4 / q^16 = q^(4-16) = q^-12 and a^-b = 1/ a^b = 1 /q^12
p^3 * 1/ q^12
p^3 / q^12
In
order to solve for a nth term in an arithmetic sequence, we use the formula
written as:<span>
an = a1 + (n-1)d
where an is the nth term, a1 is the first value
in the sequence, n is the term position and d is the common difference.
</span><span>THIRD
</span><span>A3=4+(3-1)(-5)
A3 = -6
A(3)=-2(3-1)(-5)
A3 = 20
</span><span>
FIFTH
</span>A5=4+(5-1)(-5)
A5 = -16
A(5)=-2(5-1)(-5)
A5 = 40<span>
TENTH
</span>A10=4+(10-1)(-5)
A10 = -41
A(10)=-2(10-1)(-5)
A10 = 90
Answer:
2.7
Step-by-step explanation:
3% × 90 =
(3 ÷ 100) × 90 =
(3 × 90) ÷ 100 =
270 ÷ 100 = 2.7
Hey!
So we have 6 multiplied by -12 and that is over 10
so we are multiplying a positive number by a negative number. When you do that the answer will be a negative number.
Now we have -72/10
we can simplify that more
divide the numerator and denominator by 2 because that is the largest number that is divisible by both number
now it is -36/5
The answer is -36/5
Hope this helps!
The answer is A, since 8 and 6 go together while you're trying to find the height for x.
