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3 years ago

456,000 in scientific notation

Mathematics

1 answer:

Alina [70]3 years ago

4 0

4.56•10•10•10•10•10. The dots mean multiply

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What is the slope of the line below?

maw [93]

2/3 that is the slope

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3 years ago

Central Subs made 27 sandwiches using 12 pound of turkey. How much turkey was used per sandwich

Finger [1]

27 divided by 12= 2.25 so 2.25 turkey was used in each sandwich.

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3 years ago

Jenny has 3 times as many new toys as she has favorite toys. The total number of toys is 60. How many favorite toys might Jenny

Ray Of Light [21]

Answer:Jenny has 15 favorite toys

Step-by-step explanation:

Jenny has 3 times as many new toys as she has favorite toys means that the ratio of new toys to favorite toys can be written as 3:1

Total Ratio=3+1=4

Since the total number of toys is given as 60

Amount of Favorite toys = ratio of favorite toys / Total ratio x Total number of toys

Amount of Favorite toys = 1/4 x 60=15

Therefore Jenny has 15 favorite toys.

7 0

3 years ago

Use the remainder Theorem and synthetic division to find p(3) for p(x) = x4 + x3 -x2 - 2x

maxonik [38]

You do not need to use the remainder theorem to find p(3). Just plugin 3 where the x is located in

$x^4 + x^3 - x^2 - 2x$

$3^4 + 3^3 - 3^2 - 2(3) = 93$

Answer is a.

4 0

4 years ago

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

Rasek [7]

Answer:

$\mu_{p} = p = 0.06$

And the standard error is given by:

$SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123$

And we want to find this probability:

$P(\hat p < 0.03)$

We can calculate the z score for this case and we got:

$z = \frac{\hat p -\mu_p}{\Se_p} = \frac{0.03-0.06}{0.0123}= -2.440$

And using the normal distribution table or excel we got:

$P(\hat p < 0.03)= P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

For this case we can find the mean and standard error for the sample proportion with these formulas:

$\mu_{p} = p = 0.06$

And the standard error is given by:

$SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123$

And we want to find this probability:

$P(\hat p < 0.03)$

We can calculate the z score for this case and we got:

$z = \frac{\hat p -\mu_p}{\SE_p} = \frac{0.03-0.06}{0.0123}= -2.440$

And using the normal distribution table or excel we got:

$P(\hat p < 0.03)= P(Z$

8 0

4 years ago