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Anarel [89]
3 years ago
9

chris is five times as old as Zac. in thirty years chris will be twice zac's age. how old is zac now?

Mathematics
1 answer:
viktelen [127]3 years ago
4 0
Zac's age=x
Chris's age=5x

After 30 years
Zac's age=x+30
Chris's age =5x+30=2(x+30)
5x+30=2x+60
5x-2x=60-30
3x=30
x=10
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Yours is 50 an your friends is 30
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If the perimeter of vectangle wall is 360 cm and its breath is 60cm. Find its length and also find the totalt cost of painting t
alexdok [17]

Answer:

<u>Rs. 72</u>

Step-by-step explanation:

We have 2 values here,

  • Perimeter of the rectangle = 360 cm
  • Breadth of the rectangle (b) = 60 cm.

Firstly, we must find the length of the rectangle (l).

So, according to the formula,

Perimeter = 2 (b + l)

360 = 2 (60 + l)

360 = 120 + 2l

360 - 120 = 2l

240 = 2l

120 cm = l

Now, we need to find the area of the rectangular wall & then convert it from cm² to m² as the cost of painting is given in m².

So,

Area = lb

Area = 120 × 60

Area = 7,200 cm²

Let's convert it to m² now,

7200/1000

= 7.2 m²

Given, cost of painting per m² = Rs. 10

So, the cost of painting the wall is,

10 × 7.2

= <u>Rs. 72</u>

<u>________________________________</u>

Hope it helps!

\mathfrak{Lucazz}

3 0
3 years ago
The sum of four consecutive integers is 390. Find the integers (Please show your work)
AysviL [449]

Step-by-step explanation:

The sum of three consecutive even integers is 390. What are the integers?

 

   In order to ensure the numbers are even I generally call the first

   integer 2n  because 2 multiplied by any number will always be even.

   Our consecutive even integers are:  2n, 2n+2, 2n+4

 

   2n + 2n+2 + 2n+4 = 390

   6n + 6 = 390

   6n = 384

   n = 64

 

  Our 1st integer is 2n = 2(64) = 128

  Our integers are 128, 130, 132

 

Check:  128+130+132 = 390 which is correct.

 

2) The sum of three consecutive odd integers is 99. What are the integers?

 

    Same logic applies:  An odd integer will always result from 2n+1

    So we will call our 3 consecutive odd integers   2n+1, 2n+3, 2n+5

 

   2n+1 + 2n+3 + 2n+5 = 99

   6n+9 = 99

   6n = 90

   n = 15

   Our first odd integer is 2n+1 = 2(15) + 1 = 31

   Our 3 consecutive odd integers are 31, 33, 35

 

Check:  31 +33+45 = 99  Yes

 

3)Which equation defines three consecutive odd integers that add up to 81?

A) n(n+1)(n+2)=81

B) n(n+2)(n+4)=81

C) n+(n+1)+(n+3)=81

D) n+(n+1)+(n+2)=81

E) n+(n+2)+(n+4)=81

 

We can immediately discard answers A, B because they are multiplying

instead of adding.

That leaves C, D, E

 

This question does not follow the logic I utilized in question 1 and 2. 

Assuming the first number is indeed odd and is called n

The next odd number is n+2 followed by n+4

Thus we must have:  n + (n+2) + (n+4) = 81

The answer is E

 

By the way:  The numbers are 25, 27, 29

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It is c have a nice rest of your day.
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Answer:

8 is 16 divided by 2

Step-by-step explanation:

Answer

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