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svetoff [14.1K]
4 years ago
9

Please help me fast.

Mathematics
2 answers:
Travka [436]4 years ago
8 0

Answer:

26

Step-by-step explanation:

all you have to do is count and add i took the test before

dlinn [17]4 years ago
5 0
It is c have a nice rest of your day.
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Find the distance from P to l. Line l contains points (-4,2) and (3,-5).Point P has coordinates (1,2).
Annette [7]
Hello,

A=(-4,2)
B=(3,-5)
AB≡y-2=(x+4)(-7)/7==>y=-x-2

Slope of the perpendicular: 1

y-2=(x-1)1==>y=x+1 is the equation of the perpendicular.

Intersection: y=x+1 and y=-x-2 ==>(-3/2,-1/2)=Q

|PQ|²=(-1/2-2)²+(1+3/2)²=25/2
|PQ|=5√2/2≈3.5355339059....



7 0
3 years ago
A rectangle has an area of 100 square centimeters. The base of the rectangle is 25 centimeters. What is the height of the rectan
enyata [817]
You find area by multiplying base and height.
The formula is  A=bh
so 100=25h
25 times 4 is 100
100=25*4

4cm is your answer
5 0
3 years ago
Read 2 more answers
Kevin can mow the lawn in 1.5 hours. Together, Kevin and Eric can mow the lawn in 30 minutes. How long will it take Eric to mow
xeze [42]

Answer:

45

Step-by-step explanation:

These work problems are always done in terms of fractions ie if both (Kevin & Eric) took 30mins to mow and Kevin took 1.5hrs (90mins) alone then we can make an equation like below

1/time took for both = 1/time took for Kevin + 1/time took for Eric

1/30 = 1/90+1/x    ==> calling time took for Kevin x

solving the above 1/x = 1/30-1/90

1/x=2/90

x=45

6 0
3 years ago
Solve 9x2 + 12x – 24 = 0 using the quadratic formula. A. x = 7, –1 B. C. D. x = 4, –7
Ksivusya [100]
\bf \qquad \qquad \textit{quadratic formula}\\\\

\begin{array}{lcclll}
9x^2&+12x&-24&=0\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
8 0
4 years ago
Read 2 more answers
Write the equation of a line passing through (6,-2) and perpendicular to -2x + 3y= -6
____ [38]
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.


-2x+3y=-6                 Add 2x in both sides
3y=2x-6                    Divide by 3 in both sides to isolate y
y=2/3x-6/3


The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

y=mx+b                 Substitute the given point and the previous slope found
-2=(-3/2)(6)+b       Combine like terms
-2=-9+b                 Add 9 in both sides to isolate b
7=b

The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.


4 0
3 years ago
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