Question

Find the difference of functions s and r shown below. r(x) = –x² + 3x

Answer 1

Answer:

(2x+1) -(-x^2+3x)

Step-by-step explanation:

r(x) = –x² + 3x  

s(x) = 2x + 1

find the difference of (s-r)(x)

(s- r)(x) = s(x) - r(x)

we are given with s(x)  and r(x)

to find the difference we plug both functions

(s- r)(x) = s(x) - r(x)

$(s- r)(x) = s(x) - r(x) = (2x+1) -(-x^2+3x)$

distribute negative sign inside the parenthesis

$2x+1 +x^2 -3x = x^2 -x +1$

(2x+1) -(-x^2+3x) is the way we find difference

Answer 2

Answer:

(2x + 1) - (–x² + 3x) is difference .

Step-by-step explanation:

Given : r(x) = –x² + 3x  and  s(x) = 2x + 1

To find : Find the difference of functions s and r .

Solution :  We have given that  r(x) = –x² + 3x and s(x) = 2x + 1.

Difference :

(s – r)(x) = s(x) - r(x)

              =(2x + 1) - (–x² + 3x)

              = 2x +1 + x²-3x

             = x²-x +1.

Therefore, (2x + 1) - (–x² + 3x) is difference .