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olganol [36]
3 years ago
14

Evaluate -8-(12)/4 Please help

Mathematics
1 answer:
liq [111]3 years ago
3 0

-11

Step-by-step explanation:

your always have to do division multiplication first

-8-(12)/4=

-8-3=

-11

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<img src="https://tex.z-dn.net/?f=R%20%3D%20%5Csqrt%7B%20%5Cfrac%7Bax%20-%20P%7D%7BQ%20%2B%20bx%7D%20%7D%20" id="TexFormula1" ti
Phantasy [73]

Step-by-step explanation:

r = \sqrt{ \frac{ax - p}{q + bx} } \\  {r}^{2}  =  \frac{ax - p}{q + bx}

r² (q + bx) = ax - p

qr² + bxr² = ax - p

qr² + p = ax - bxr²

qr² + p = x (a - br²)

x =  \frac{q {r}^{2}  + p}{a - b {r}^{2} }

7 0
4 years ago
Read 2 more answers
Can I get some help please? Show your work <br><br> Thanks!
grigory [225]
Hey Gary :) Nice to see you around

For this question, we want to use logarithmic rules to write the expression as a single logarithm.
Using the rule log_{b} ( M^{k} ) = k *  log_{b} M , we can simplify 
3log_{b} q to log_{b} ( q^{3} ) . We can also simplify 6log_{b}(v) to log_{b}( v^{6}) .

So, we have log_{b} ( q^{3} ) + log_{b}( v^{6}).

Another logarithmic rule is:
log_{b}(M*N) =  log_{b} M +  log_{b} N&#10;

Using this rule, we can use the logs we have calculated and change them to:
log_{b}( q^{3}  v^{6})

This matches answer choice A.

Hope this helps! Feel free to contact me with any questions.


4 0
3 years ago
The value of y varies directly with x. When y=75,x=1/2. What is the value of y when x is 3 3/4?
True [87]

Honestly not sure at all


7 0
3 years ago
Which numbers have an absolute value of 4?(you can pick more than one)<br><br> 4<br> -4<br> 2<br> 8
oksian1 [2.3K]

Answer:

4 and -4

Step-by-step explanation:

absolute value is always going to be positive and the overall value will only change if it is negative. so the "|4|" (absolute value of 4) is the same as "|-4|" (absolute value of negative 4)

3 0
3 years ago
Read 2 more answers
Hasil darab umur
Alex787 [66]

Answer:

nojkl.kj

Step-by-step explanation:

lklkjl,kjkl

3 0
3 years ago
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