Use the chain rule:

We have


so we get

Alternatively, you can substitute <em>u</em> in the definition of <em>y</em> and differentiate with respect to <em>x</em> :

Answer:
0.4
Step-by-step explanation:
x=2/5
2/5=0.4
Answer:
Doesn't have solution.
Step-by-step explanation:
x ≠ 0; x > 0 (I)
x - 5 > 0
x > 5 (II)
![log_6 x + log_6 (x + 5) = 2 \\\ log_6 [x(x + 5)] = 2 \\\ x^2 + 5x = 36 \\\ x^2 + 5x - 36 = 0 \\\ \Delta = 5^2 - 4.1.(- 36) \\\ \Delta = 169 \\\ \sqrt{\Delta} = \pm 13 \\\ x' = \frac{- 5 + 13}{2} \\\\ x' = 4 \\\ x" = \frac{- 5 - 13}{2} \\\\ x" = - 9](https://tex.z-dn.net/?f=log_6%20x%20%2B%20log_6%20%28x%20%2B%205%29%20%3D%202%20%5C%5C%5C%20log_6%20%5Bx%28x%20%2B%205%29%5D%20%3D%202%20%5C%5C%5C%20x%5E2%20%2B%205x%20%3D%2036%20%5C%5C%5C%20x%5E2%20%2B%205x%20-%2036%20%3D%200%20%5C%5C%5C%20%5CDelta%20%3D%205%5E2%20-%204.1.%28-%2036%29%20%5C%5C%5C%20%5CDelta%20%3D%20169%20%5C%5C%5C%20%5Csqrt%7B%5CDelta%7D%20%3D%20%5Cpm%2013%20%5C%5C%5C%20x%27%20%3D%20%5Cfrac%7B-%205%20%2B%2013%7D%7B2%7D%20%5C%5C%5C%5C%20x%27%20%3D%204%20%5C%5C%5C%20x%22%20%3D%20%5Cfrac%7B-%205%20-%2013%7D%7B2%7D%20%5C%5C%5C%5C%20x%22%20%3D%20-%209)
Then, this expression doesn't have solution.
I Hope I've helped you.
Slope = 5
y = mx + b
2 =5(4) + b
b = 2 - 20
b = -18
<span>point-slope equation
y - 2 = 5(x -4)
</span><span>slope-intercept equation
y = 5x - 18
standard form
5x - y = 18</span>