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saw5 [17]
3 years ago
5

2x-3x^3+8 in standard form

Mathematics
1 answer:
larisa [96]3 years ago
8 0
3x³ -2x - 8 = 0


......,...........,
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5/4 = equals what like I need an answer
defon

In decimal form, 5/4 is equal to 1.25

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Solve for x 21 27 x-3 x-1
Nataly_w [17]

Answer

27x^22-3x-1

hope this is right!!

Step-by-step explanation:

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2 years ago
Two parallel lines, cut by transversal, are shown. One of the acute angles formed measures 80. Find the measures of all the othe
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The one across it is 100 and on both sides 

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3 years ago
Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6
kirill [66]

Answer:

Option (a) is correct.

The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Step-by-step explanation:

Given : Equation  12x^3-5x=2x^2+x+6

We have to construct a  system of equations that  can be used to find the roots of the equation 12x^3-5x=2x^2+x+6

Consider the given equation 12x^3-5x=2x^2+x+6

To construct a system of equation put both sides of the given equation equal to a same variable.

Let the variable be "y", Then the equation 12x^3-5x=2x^2+x+6

becomes,

12x^3-5x=y=2x^2+x+6

Thus, The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Option (a) is correct.

   

8 0
3 years ago
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17. Two tanks are similar in shape. The capacity of the tanks are 1,000,000 litres and 512, 000 liters respectively
Gnesinka [82]

Given that, Two tanks are similar in shape. The capacity of the tanks are 1,000,000 litres and 512, 000 liters respectively.Find the height of the smallest tank if the larger is 300cm tall?

Assume that, the tanks are rectangular in shapes and differ only on their heights. The volume of the larger tank is

V1 = l × w × h1 while the volume of the smaller tank is V2 = l ×w × h2. The ratios of the capacities is

\sf \frac{V1}{V2} = l  \times  w  \times h1  \times  w  \times  h2 =  \frac{h1}{h2}

Solving for the height of the smaller tank h2

\sf \frac{V1}{V2} =  \frac{h1}{h2}

\sf\frac{1000000} {51200} = \frac{ 300 cm }{ h2}

1000000 × h2 = 51200 × 300 cm

h2 = (51200 × 300 cm) /1000000

h2 = 15.36 cm

\sf\implies \: \boxed{ \bf{ \: Height \:  of  \: the \:  smaller  \: tank  \: is  \: 15.36 cm.\: }}

{ \underline {\rule{5000pt}{6pt}}}

5 0
2 years ago
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