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3 years ago

Someone please help me

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

4 0

9514 1404 393

Answer:

14.09 square units

Step-by-step explanation:

The desired area is the area of the full circle, multiplied by the fraction that is shaded. That fraction is the ratio of the sector central angle to the central angle for a whole circle: 42°/360°.

A = πr²(d/360)

A = 3.14159(6.2²)(42/360) ≈ 14.09

The area of the shaded sector is about 14.09 square units.

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3*5*2 please ans me hope you can help

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Answer:

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Step-by-step explanation:

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Circle A has an area of 500 in.². The diameter of the circle B is three times the diameter of Circle A. Estimate the area of cir

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R^2π=500in^2
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3 years ago

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Answer:

The zeros are the points where the parabola intercepts the x-axis.

$\sf x = 7 \implies x - 7 = 0$

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So the equation of the parabola is:

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2 years ago

What is the multiplicative identity matrix? What is it similar to in the set of real numbers? Explain your answer

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Answer:

An identity matrix, is a matrix that have '1' in the main diagonal. All of the other terms are '0'. When you multiply any matrix by the identity matrix, the result is the same matrix that you multiplied.

Example:

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$

In the set of the real number is the same that the application of identity property.

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Step-by-step explanation:

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3 years ago

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miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* Lets the meaning of vertical and horizontal asymptotes

- Vertical asymptotes are vertical lines which correspond to the zeroes

of the denominator of a rational function

- A horizontal asymptote is a y-value on a graph which a function

approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

then there is a horizontal asymptote at y = leading coefficient of the

numerator ÷ leading coefficient of the denominator

* Lets solve the problem

∵ $f(x)=\frac{6x}{x+2}$

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ The horizontal asymptote can be described by the line y = 6

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

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- Subtract 2 from both sides

∴ x = -2

∴ The vertical asymptote can be described by the line x = -2

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