Answer:
The given quadrilateral is a parallelogram.
Step-by-step explanation:
If a quadrilateral is a parallelogram , then the opposite sides would be equal.
Here we are going to equate the length of 1 pair of opposite sides to find the value of x and use this value of x to verify whether the other pair of opposite sides are equal.
AB = 6x
BC = 3x
DC = x + 15
AD = 9
Equate AB and CD,
6x = x + 15
5x = 15
x = 3
Now BC and DA should be equal.
BC = 3x = 9
Also DA = 9
As we can see, the other pair of opposite sides are also equal.
Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.
Hence , the given quadrilateral is a parallelogram.
In form
ax+by=c
slope=-a/b
y intercpept=c/b
so
-3x-4y=-12
a=-3
b=-4
c=-12
slope=-(-3)/-4=3/-4=-3/4
yint=-12/-4=3
slope=-3/4
yint is 3
Answer:
(x^2 + 2x - 21) sq units
Step-by-step explanation:
Area of the shaded region = Area of the larger rectangle - Area of smaller rectangle
Area of the larger region = x(x+2)
Area of the larger region =x^2 + 2x
Area of the smaller rectangle = 3 * 7
Area of the smaller rectangle = 21 sq. units
Area of the shaded region = x^2 + 2x - 21
Hence the required expression is (x^2 + 2x - 21) sq units
b
a and d should not be considered bc it is not logically correct. c is eliminated because that may not always be the case. therefore it should be b.
Answer:
6
Step-by-step explanation:
1/2 * 1/2 * 2 * 12 =
1/2 * 12 (because the 1/2 and 2 cancel out, as they form 1) =
6
