Question

What is the volume of grain that could completely fill this silo, rounded to the nearest whole number? Use 22 over 7 for pi.

Answer 1

Find the volume of the bottom and top separately and then add them. Cylinder volume is the area of the bottom times the height (22/7)(5^2)•175=13750 ft^3
The volume of a sphere isV=(4/3)(22/7)r^3where r is the radius.  also 5 since it fits on the cylinder. Also we only want half the sphere so useV=(2/3)(22/7)•5^3=261.9 ft^3 round upto 262. Now add  together 13750+262=14,012 ft^3
Hope this helps~!!!!!

Answer 2

Answer:

The answer is 14,012 ft^3

Step-by-step explanation:

In order to find the volume of grain that could completely fill the silo, we need to determine the volume of the sphere and cylinder that make up the silo.

Note: 22/7 is pi in fraction form

Sphere:

V =  4/3π r^3  

 = 4/3(22/7)(5)^3

 = 4/3(22/7)(125)

 = 4/3 (22*125/7)

 = 4/3 (393)

 = 4/3 (392.9/1)

 = 524

If we look at the attached picture we notice that the sphere is cut in half, so we'll divide the volume by 2

V = 262

We're not done yet, we still have to find the volume of the cylinder...

Cylinder:

V = π r^2h

 = 22/7(r^2)h

 = 22/7(5)^2(175)

 = 22/7(25)(175)

 = 22/7(4375)

 = 22/7(4375/1)

V = 13750

Finally, we add the two volumes together and we get...

 = 13750 + 262

 = 14,012

V = 14,012 ft^3

I really hope this helps, good luck in geometry!