3 years ago

What is the approximate circumference of a circle with the diameter of 9

Mathematics

1 answer:

WINSTONCH [101]3 years ago

6 0

Answer:

9pi

Step-by-step explanation:

circumference is 2(pi)(r) or diameter(pi)

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Agata [3.3K]

Answer:

- 2 feets

Step-by-step explanation:

Given that sea star can be found at an ocean depth of 2 feets ;

An ocean depth of 2 feets can be represented as :

Sea level - depth = 0 - 2 = - 2 feets

Hence, it can be concluded that sea star lives in the ocean

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3 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y

DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

$\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}$

And:

$y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}$

If we apply these two to our initial expression, we can rewrite it as:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y}$

$\sqrt{y^3} + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}$

Here we can use the second simplification again, to rewrite:

$\sqrt{y^3} = y*\sqrt{y}$

So, concluding, we have:

$\sqrt{y^3} + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}$

Then the correct option is C.

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3 years ago

find the image of (2,4)obtained by translating 2 units down followed by a rotation of 180° counterclockwise about the origin

enot [183]

Answer:

(-2,-2)

Step-by-step explanation:

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3 years ago