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Leviafan [203]
3 years ago
11

Ow many solutions does the system of equations –6a + b = 14 and –12a + 2b = 28 have?

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0
Indefinite amount of solutions.
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Find the sum of the first one hundred positive integers. see fig 6.26
nignag [31]
Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
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This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.

Quick note
We can use a formula to find out the sum of an arithmetic series:
s =  \frac{n(n + 1)}{2}
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.
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Witch is bigger -5 or -55
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The answer to which is bigger is -5 because it is closer to zero
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A shopkeeper allows 10% discount on the marked price of a bicycle. If a costomer pays Rs 4068 with 13% VAT find the marked price
Over [174]

\large{ \tt{❁ \: S \: O \: L \: U \: T \: I \: O \: N \: ❁}}

  • We're provided - Discount % = 10 % , Cost with VAT [ SP with VAT ] = Rs 4068 & VAT % = 13%. We're asked to find out the marked price of the bicycle. Let's start :

\large{ \tt{❇ \: FIND \: SP \: WITHOUT \: VAT \: / \: SP\: ❇}}

\large{ \tt{❃ \: SP  \: with \: VAT= SP + VAT\% \: of \: SP}}

\large{ \tt{⇢ \: 4068 = SP + 13\% \: of \: SP}}

\large{ \tt{⇢ \: 4068 = SP +  \frac{13}{100}  \: sp}}

\large{ \tt{⇢ \: 4068 =  \frac{100 \:  \: SP + 13 \: SP}{100} }}

\large{ \tt{⇢ \: 4068 =  \frac{113 \: SP}{100} }}

\large{ \tt{⇢ \: 113 \: SP = 406800}}

\large{ \tt{⇢ \: SP =  \frac{406800}{113} }}

\large{ \tt{⇢ \: SP = 3600}}

  • Hence , SP = Rs 3600

\large{ \tt{✽ \: NOW , \: FIND \: THE \: MP \:✽ }}

  • Let Marked Price [ MP ] be x.

\large {\tt{❃ \: SP = MP - dis\% \: of \: MP}}

\large{ \tt{⇾ \: 3600 = x - 10\% \: of \: x}}

\large{ \tt{⇾ \: 3600 = x -  \frac{10}{100} } \: x}

\large{ \tt{⇾ \: 3600 =  \frac{100x - 10x}{100} }}

\large{ \tt{⇾ \: 3600 =  \frac{90x}{100} }}

\large{ \tt{⇾ \: 90x = 360000}}

\large{ \tt{⇾ \: x =  \frac{360000}{90} }}

\large{ \tt{⇾ \: x = Rs \: 4000}}

\large{ \boxed{ \boxed{ \tt{☂ \: OUR \: FINAL \: ANSWER :  \boxed {\tt {\: Rs \: 4000}}}}}}

  • Hope I helped! Let me know if you have any questions regarding my answer and don't hesitate to reach out to me if you need any assistance! :)
6 0
3 years ago
O.9c + 1.89r = 17.01 c=18.9 - 2.1r equation answer
ikadub [295]

Answer:

c=18.90-2.1r

Step-by-step explanation:

<u><em>The complete question is</em></u>

A chef bought $17.01 worth of ribs and chicken. Ribs cost 1.89 per pound and chicken costs 0.90 per  pound. The equation 0.90 +1.89r = 17.01 represents the relationship between the quantities in this  situation.

Show that each of the following equations is equivalent to 0.9c + 1.89r = 17.01.

Then, explain when it might be helpful to write the equation in these forms.

a. c=18.9-2.1r. b. r= -10÷2c+9​

we have that

The linear equation in standard form is

0.90c+1.89r=17.01

where

c is the pounds of chicken

r is the pounds of ribs

step 1

Solve the equation for c

That means ----> isolate the variable c

Subtract 1.89r both sides

0.90c=17.01-1.89r

Divide by 0.90 both sides

c=(17.01-1.89r)/0.90

Simplify

c=18.90-2.1r

step 2

Solve the equation for r

That means ----> isolate the variable r

Subtract 0.90c both sides

1.89r=17.01-0.90c

Divide by 1.89 both sides

r=(17.01-0.90c)/1.89

Simplify

r=9-0.48c

therefore

The equation c=18.90-2.1r is equivalent

The equation is helpful, because if I want to know the number of pounds of chicken, I just need to substitute the number of pounds of ribs in the equation to get the result.

4 0
3 years ago
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