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2 years ago

Determine the total number of roots of each polynomial function. f (x) = 3x6 + 2x5 + x4 - 2x3

Mathematics

2 answers:

Oxana [17]2 years ago

8 0

Answer:

6 roots

Step-by-step explanation:

we know that

The number of roots is determined by the degree of the polynomial. They may be real or complex.

In this problem we have

$f(x)=3x^{6}+2x^5+x^4-2x^3$

The degree refers to the highest exponent of the polynomial

Since this is a 6th degree polynomial, it will have 6 roots

Dmitry_Shevchenko [17]2 years ago

7 0

Answer: 6

Step-by-step explanation:

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Answer: the answer is C

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Answer correctly please !!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!

valina [46]

Answer:

74º

Step-by-step explanation:

Ray TV bisects ∠RTS, so ∠RTV=∠STV=(16x-6)º
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2 years ago

Tickets for a play cost $4 for each child and $8 for each adult. If there are only 20 children's tickets sold, which of the foll

dimaraw [331]

What are the answer choices?

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1 year ago

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

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2 years ago

Subtract.

notka56 [123]

-2 4/7 is your answer

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2 years ago

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