Split up the interval [0, 2] into 4 subintervals, so that
![[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]](https://tex.z-dn.net/?f=%5B0%2C2%5D%3D%5Cleft%5B0%2C%5Cdfrac12%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac12%2C1%5Cright%5D%5Ccup%5Cleft%5B1%2C%5Cdfrac32%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac32%2C2%5Cright%5D)
Each subinterval has width
. The area of the trapezoid constructed on each subinterval is
, i.e. the average of the values of
at both endpoints of the subinterval times 1/2 over each subinterval
.
So,


Answer:
–13
Step-by-step explanation:
<h2>—Math </h2>
h(x) = –x –4
h(x) = 9
–x –4 = 9
–x = 9 + 4
–x = 13
x = –13
<em><u>pick me as the brainliest. thx</u></em>
If you can't see the picture the answer is: (y+4)(y+2).
Hope this helps, and May the Force Be With You!
-Jabba
Write the standard form of a line, the slope is 5/2 since they are parallel and then replace the coordinates.
y-(-29) = 5/2 (x-(-6)) -> y=5/2x-14
Answer:
Step-by-step explanation:
11 - 19 - 4 - (-8) =
11 - 19 - 4 + 8 =
- 23 + 19 =
- 4 <===