Given that the half life of 3H is 12.3 years.
The amount of substance left of a radioactive substance with half life of

after t years is given by

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
Answer:
Hence x = y = 2
Step-by-step explanation:
Using the SOH CAH TOA identity
Hypotenuse = 2√2
Opposite = x
theta = 45
Sin theta = opp/hyp
Sin 45 =x/2√2
1/√2 = x/2√2
x = 2√2 * 1/√2
x = 2
To get y we will use the pythagoras theorem;
(2√2)² = x² +y²
(2√2)² = 2²+y²
8 = 4 + y²
y² = 8-4
y² = 4
y = √4
y = 2
Hence x = y = 2
Answer:
Answer is – 3
Step-by-step explanation:
expand the expression using ( a – b) ( a + b) = a² –b²
( 3 ) ² – ( 6) ² *remember to place your square roots inside the brackets my phone doesn't have one*
then simplify the radical
3–6 = – 3
Y = yearbook club
d = drama club
y + d = 84
d = y + 16
now we sub y + 16 in for d in the first equation
y + d = 84
y + (y + 16) = 84
2y + 16 = 84
2y = 84 - 16
2y = 68
y = 68/2
y = 34 <=== yearbook club students
d = y + 16
d = 34 + 16
d = 50 <=== drama club students