Fredrick threw a ball from the top of a building. The height of the ball, in feet, after it is thrown is modeled by the function
1 answer:
Answer:
5.2seconds
Step-by-step explanation:
Fredrick threw a ball from the top of a building. The height of the ball, in feet, after it is thrown is modeled by the function
The modeled function is given as
h(t) = –16t^2 +64t + 100,
We can see this is a quadratic equation, we can solve using quadratic formula, Below
= -b±(√b^2 -4ac)/2a
Where
a=-16, b=64, c=100
FROM THE ATTACHMENT
We have too answers t= -1.20s and t=5.20s
Therefore,it take 5.20s for the ball to reach the ground (h=0). Because "t" cannot be negative here
CHECK THE ATTACHMENT FOR THE QUADRATIC SOLUTION
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Answer: The ramp would be 15.5 feet long.
Step-by-step explanation: Please refer to the attached diagram for details.
Angle C shows the angle to be formed by the ramp from the ground, which is 15 degrees. Also, from the ground, it’s going to be four feet tall, which is line AB. The top of the ramp is point A, which makes line AC the entire length of the ramp. Since we have a reference angle (angle C) and two sides, the opposite and the hypotenuse, we shall apply the trigonometric ratio.
SinC = opposite/hypotenuse
Sin 15 = 4/b
By cross multiplication we now have
b = 4/Sin15
b = 4/0.2588
b = 15.4599
Approximately b = 15.5
Therefore the length of the ramp would be 15.5 feet
