Answer:
y = 5x2 + 10x - 15
We want this in format y = a(x-h)2 + k
where the vertex will be at (h,k)
y = 5(x2+2x) - 15
Complete the square on x2+2x
y = 5(x2+2x+1) - 15 - 5
We subtract 5 at the end because we are actually adding 5(1) = 5
so we need to remove it also to keep the total equal
y = 5(x+1)2 - 20
The vertex is at (-1,-20)
Answer:
Many reasons
Step-by-step explanation:
Is there an asymptote?
Is there a whole?
Is it a vertical or horizontal line?
What's the specific function?
Answer:
Below
Step-by-step explanation:
Let's say that each square on the grid represents 1 cm
First find the area of the two triangles
For the larger one: A = bh/2
A = 3 x 3 / 2
= 4.5 cm^2
For the smaller one : A = bh/2
A = 2 x 2 / 2
= 2 cm^2
For the rectangle : A = lw
A = 4 x 5
= 20 cm^2
Add them all up to get the area
4.5 + 2 + 20 = 26.5 cm^2
Hope this helps!
We know that
A line tangent to a circle is perpendicular to the radius to the point of tangency.
so
<span>Line ef is </span>perpendicular to the segment gh
hence
Triangle FHG is a right triangle
Answer:
<h2>Area Semicircle = 1/2 πr² </h2>
where
r radius of semicircle
→ ½ * 22/7 * r² = 35
→ 11/7 * r² = 35
→ r² = 35*7/11
→ r² = 245/11
→ r² = 22.77
→ r = √22.77
→ r = 4.77
Therefore,
Diameter = 2*4.77
= 9.54 cm
