Answer: 
Step-by-step explanation:
A line that cuts a circle at two points is called "secant".
There is a theorem known as "Intersecting Secant Theorem". This is the theorem you need to use to find the value of "d".
According the Intersecting Secant Theorem:

Having this expression, the next step is to solve for "d":
Use Distributive property:

Subtract 256 from both sides:


Divide both sides by 16:

The value of "d" rounded to the nearest tenth is:

Answer:
B
Step-by-step explanation:
Multiplying both sides of <span>−1/3x≤−6 by -3 results in "x is equal to or greater than 18."
Note that multiplying such an inequality requires reversing the direction of the inequality symbol.
I subst. 18 for x in </span><span>−1/3x≤−6 as a check, and found that the resulting inequality is true.</span>
Answer:
Step-by-step explanation:
hello :
Part A : x+6y =6 means : 6y = - x+6
so : y = (-1/6)x+1 an equation for the line (D)
y = (1/3)x -2 is the line (D')
PartB : solution of the system : y = (-1/6)x+1 ....(1) color red
y = (1/3)x -2 ....(2) color bleu
is the intersection point : (6 ; 0)
PartC : Algebraically by (1) and (2) : (-1/6)x+1 = (1/3)x -2
(-1/6)x - (1/3)x = -2-1
(-x-2x)/6= -3
-3x = -18
so : x = 6 put this value in (1) or (2) : y = (-1/6)(6)+1 =0 the solution is : (6 ;0)