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Arisa [49]
2 years ago
14

The ratio of the measures of the three angles in a triangle is 2:9:4. Find the measures of the angles. ​

Mathematics
1 answer:
Alex777 [14]2 years ago
8 0

Answer:

Let the three angles be 2x,9x & 4x

By the problem,2x+9x+4x=180

15x=180

x=180/15

x=12

there fore the angles are

2x= 2*12=24°

9x=108°

4x=48°

Step-by-step explanation:

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A sofa regularly sells for 860. The sale price is 670.80. Find the percent decrease of the sale price from the regular price
andre [41]

Answer:

-22%

Step-by-step explanation:

The percent decrease can be found by subtracting the original amount from the sale price. Divide the result by the original price and multiplying the decimal by 100 for the percent.

670.80 - 860 = -189.2

-189.2/860 = -0.22

-0.22*100 = -22%

4 0
3 years ago
Hi please help I’m rlly behind in school!!!
Butoxors [25]

Answer:

17 pounds

Step-by-step explanation:

Median:

Weights of the dogs are:

3 , 8 , 10 , 11 , 14 , 17 , 22 , 24, 25 , 35 , 40

Number of data = 11

So, median will the middle term which is the 6the term.

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4 0
2 years ago
Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenu
Ede4ka [16]

Answer: The area common to both triangle is 31.77 sq. cm.

Step-by-step explanation:

Since we have given that

30-60-90 triangles are placed.

So, the ratio of sides would be

1:\sqrt{3}:2

Since Hypotenuse = 12 cm

So, it becomes,

2x=12\\\\x=\dfrac{12}{2}=6

So, Base would be

x=6\ cm

and Perpendicular would be

\sqrt{3}x=6\sqrt{3}

So, Area common to the both triangles would be

\dfrac{1}{2}\times base\times height\\\\=\dfrac{1}{2}\times 6\times 6\sqrt{3}\\\\=18\sqrt{3}\\\\=31.177

Hence, the area common to both triangle is 31.77 sq. cm.

4 0
3 years ago
Four students simplified the expression.
Viktor [21]

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6 0
3 years ago
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The National Science Organization is monitoring the continuous exponential decline of an insect species due to deforestation. Th
kakasveta [241]

Answer:

P\geq 26e^{-0.079t}

P\geq 2

Step-by-step explanation:

We are given that there is an exponential decay.

Also, the decrease is of constant rate 7.9% i.e. 0.079 each year.

Since, the initial amount of the species is atleast 26 million.

Thus, the inequality for the corresponding model will be, P\geq 26e^{-0.079t},

where t is the time period for the decay and P is the population.

Moreover, is is given that the population cannot be less than 2 million.

So, we get, P\geq 2.

Hence, the inequalities to determine the possible number of insects over time are given by,

P\geq 26e^{-0.079t}

P\geq 2.

4 0
3 years ago
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