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o-na [289]
4 years ago
8

Help!!! What is the 7th term in the geometric sequence in which a10 is 9 and a13 is -72????????

Mathematics
1 answer:
MArishka [77]4 years ago
5 0
A10 =9
a11= 9 x -2 = -18
a12= -18 x -2 = 36
a13 =36 x -2 = -72

multiplies by -2 every time
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You just have to draw to circles on top and tree circles on bottom and you just have to draw a line on circle on the three and on circle on the other three and you just count how many lines there are but i just did it in my head 
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3 years ago
40.quadrilateral efgh was translated 3 units to the left and 8 units up to create quadrilateral e' f'g'h'. which
Kipish [7]

Answer:

translation

Step-by-step explanation:

6 0
2 years ago
Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
Read 2 more answers
Factor 24m - 12p + 72 to identify the equivalent expressions.
LUCKY_DIMON [66]

Answer:

B and C

Step-by-step explanation:

If you take the least common factor you'd see that it could be factored to 2(12m-6p+36)

If you take the greatest common factor then it could be factored to 12(2m-p+6)

8 0
3 years ago
PLS PLS help!
Leto [7]

9514 1404 393

Answer:

  y = 3x^2 +30x +69

Step-by-step explanation:

Transformations work this way:

  g(x) = k·f(x) . . . . vertical stretch by a factor of k

  g(x) = f(x -h) +k . . . . translation (right, up) by (h, k)

__

So, the translation down 2 units will make the function be ...

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The vertical stretch by a factor of 3 will make the function be ...

  f1(x) = x^2 -2  ⇒  3·f1(x) = f2(x) = 3(x^2 -2)

The horizontal translation left 5 units will make the function be ...

  f2(x) = 3(x^2 -2)  ⇒  f2(x +5) = f3(x) = 3((x +5)^2 -2)

The transformed function equation can be written ...

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The attachment shows the original function and the various transformations. Note that the final function is translated down 6 units from the original. That is because the down translation came <em>before</em> the vertical scaling.

4 0
3 years ago
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