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Paul [167]
3 years ago
14

a parallelogram has an area of 108 square inches . the base of the parallelogram is 18 inches . explain how you could find the h

eight of the parallelogram

Mathematics
1 answer:
Roman55 [17]3 years ago
5 0
Parallelogram height = 2 * Area / base
Parallelogram height = 2 * 108 / 18
Parallelogram height = 216 /18
Parallelogram height = 12

Source:
http://www.1728.org/quadpar.htm


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Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
The midpoint of AB is M(-5,1). If the coordinates of A are (-4,-5), what are the coordinates of B?
Elenna [48]

<u>ANSWER:</u>

The midpoint of AB is M(-5,1). The coordinates of B are (-6, 7)

<u>SOLUTION: </u>

Given, the midpoint of AB is M(-5,1).  

The coordinates of A are (-4,-5),  

We need to find the coordinates of B.

We know that, mid-point formula for two points A(x_{1}, y_{1}) and B (x_{1}, y_{2}) is given by

M\left(x_{3}, y_{3}\right)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

Here, in our problem, \mathrm{x}_{3}=-5, \mathrm{y}_{3}=1, \mathrm{x}_{1}=-4 \text { and } \mathrm{y}_{1}=-5

Now, on substituting values in midpoint formula, we get

(-5,1)=\left(\frac{-4+x_{2}}{2}, \frac{-5+y_{2}}{2}\right)

On comparing, with the formula,

\frac{-4+x_{2}}{2}=-5 \text { and } \frac{-5+y_{2}}{2}=1

-4+\mathrm{x}_{2}=-10 \text { and }-5+\mathrm{y}_{2}=2

\mathrm{x}_{2}=-6 \text { and } \mathrm{y}_{2}=7

Hence, the coordinates of b are (-6, 7).

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1374 multiplied by 6 would be 8244

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Answer:

  • B) 2º+2=4

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raise ^to the power -2 like this

5-2=3 <Awnser

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Which of these represents categorical data?
Viktor [21]

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the answer is D) the most popular foods in the cafeteria

~batmans wife dun dun dun....

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