Yeah!! In absolute value, you have to darken all the way to the negative of that value in addition of its real value.........
Suppose, you have to describe absolute value of 3 on a graph, then you have to mark the line from -3 to 3
16m cubed - 10m squared......
take out the common factors
they both have a two that can go into it and both have two m's you can take out
so then it becomes
2m squared(8m-5) and thats your answer (:
Answer:
136
Step-by-step explanation:
For this case we have the following function:
f (t) = -16t2 + 48t + 100
The average rate of change is:
(f (t2) - f (t1)) / (t2 - t1)
We have then:
For t1 = 3:
f (3) = -16 * (3) ^ 2 + 48 * (3) + 100
f (3) = 100
For t2 = 5:
f (5) = -16 * (5) ^ 2 + 48 * (5) + 100
f (5) = -60
Substituting values:
AVR = (-60 - 100) / (5 - 3)
AVR = -80
Answer:
The average rate of change of f (t) from t = 3 seconds to t = 5 seconds is -80 feet per second.
