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lesya692 [45]
2 years ago
6

20. What volume of 0.350M KMnO4 solution must be diluted to prepare 600. mL of

Chemistry
1 answer:
Dafna1 [17]2 years ago
3 0

Answer:

25.7 mL

Explanation:

Step 1: Given data

  • Initial volume (V₁): ?
  • Initial concentration (C₁): 0.350 M
  • Final volume (V₂): 600 mL
  • Final concentration (C₂): 0.150 M

Step 2: Calculate the volume of the initial solution

We have a concentrated solution and we want to prepare a diluted one. We can calculate the initial volume using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.150 M × 600 mL / 0.350 M

V₁ = 25.7 mL

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Explanation:

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A. H₂O or H₂S

H₂S. S is below O in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

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\bold{\huge{\underline{\purple{ Answer }}}}

<u>Difference </u><u>between </u><u>Atomic </u><u>mass</u><u>, </u><u>relative </u><u>atomic </u><u>mass </u><u>and </u><u>average </u><u>atomic </u><u>mass</u><u> </u><u>:</u><u>-</u>

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