Answer:
152.4 g of O₂ are consumed.
Explanation:
We start from the combustion reaction:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We convert the mass of propane to moles:
41.9 g . 1mol /44g = 0.952 moles
Ratio is 1:5. 1 mol of propane consumes 5 moles of oxygen at propane combustion
Then, 0.952 moles may consume (0.952 . 5) /1 = 4.76 moles.
We convert moles to mass → 4.76 mol . 32g/mol = 152.4 g
0.6675 moles of solute are present in .75 l of a .89 m (molar) solution.
<h3>Define the molarity of a solution.</h3>
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.
Given data:
V= 0.75
M=0.89
Molality = 
0.89 M= 
Moles= 0.6675
Hence, 0.6675 moles of solute are present in .75 l of a .89 m (molar) solution.
Learn more about the moles here:
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i think it is 8. I might be wrong.
Properties of a compound is completely different from their elements.
Water is composed by hydrogen and oxygen.
For example, the boiling point of oxygen is - 183 °C and hydrogen is - 253 °C, meanwhile, water has a boiling point of 100°C
Another example is when you put a burning wooden splint into oxygen, it burns more brightly. Put it in hydrogen, you may hear a "pop" sound, or even explode when large amount of hydrogen. But if u put a burning splint in water, it goes off.