ΔT = 46.6 - 20
ΔT = 26.6ºC
<span>Specific heat of
water is 1.0 cal/g °C
</span>
Q = m * C * ΔT
5650 = m * 1.0 * 26.6
5650 = m * 26.6
m = 5650 / 26.6
m = 212.4 g
hope thips helps!
Answer:
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Answer:
The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)
Explanation:
Step 1: Data given
2.0 M Al(NO3)3
Step 2:
Al(NO3)3 in water will dissociate as following:
Al(NO3)3 → Al^3+ + 3NO3^-
For 1 mol of Al(NO3)3 we will have 1 mol of Al^3+ and 3 moles of NO3^-
We know that the molarity of Al(NO3)3 = 2.0 M, this means 2.0 mol/ L
The mol ratio Al(NO3)3 and Al^3+ is 1:1 so the molarity of Al^3+ is<u> 2.0 M</u>
The mol ratio Al(NO3)3 and NO3^- is 1:3 so the molarity of NO3^- is<u> 6.0M</u>
The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)
<span>"If they recover 10.5 it means you shall add with the limiting 10.8, giving you 21.3g out of 142 times 100, giving 15%, I believe."
By anonymous on openstudy.com
</span>
Answer: low pH
Hydronium is H^+ and acids give hydronium ions to water solution.
PH = -log H^+ concentration. The higher the concentration, the lower pH value
