Answer:
44.7 degree (3 s.f)
Explanation:
mass of water = 4.10Kg
Initial temperature = 37.5C
Final temperature = x
Heat = 125 kJ = 125000 J
Specific heat capacity = 4180 J/kg°C
These parameters are given by:
H = MCΔT
ΔT = H / MC
ΔT = 125000 / (4.10 * 4180)
ΔT = 7.294
ΔT = T2 - T1
T2 = ΔT + T1
T2 = 7.294 + 37.5
T2 = 44.794 = 44.7 degree (3 s.f)
Answer:
200 grams of sodium hydroxide produce 595 grams of sodium sulfate if we have an excess of sulphuric acid
Explanation:
2 NaOH + H2SO4 → 2 H20 + Na S04
From the above chemical equation we can state that
2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate.
Now if we start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid then the amount in grams of sodium sulfate will be formed
2 moles of sodium hydroxide produce 1 mole of sodium sulfate.
In term of mass, we can say that
40 grams of sodium hydroxide produce 119grams of sodium sulfate
1 grams of sodium hydroxide produce (119/40) grams of sodium sulfate
then 200 grams of sodium hydroxide produce ((119*200)/40) grams of sodium sulfate
or 200 grams of sodium hydroxide produce 595 grams of sodium sulfate
<span>the Steps of the Carbon Cycle</span>
Answer:
- <em>The unknown integer X in the formula is </em><u>5</u><em>.</em>
Explanation:
<u>1) Data:</u>
a) Mass of CuSO₄ ∙ XH₂O = 1.50 g
b) Mass of CuSO₄ = 0.96
c) X = ?
<u>2) Additional needed data:</u>
a) Molar Mass of CuSO₄ = 159,609 g/mol
b) Molar mass of H₂O = 18,01528 g/mol
<u>3) Chemical principles and formulae used:</u>
a) Law of conservation of mass
b) Molar mass = mass in grams / number of moles = m / n
<u>4) Solution:</u>
a) Law of conservation of mass:
- Mass of CuSO₄ ∙ XH₂O = mass of CuSO₄ + mass of H₂O
- 1.50g = 0.96g + mass of H₂O ⇒ mass of H₂O = 1.50g - 0.96g = 0.54g
b) Moles
- CuSO₄: n = 0.96g / 159.609 g/mol = 0.0060 mol
- H₂O: 0.54g / 18.01528 g/mol = 0.030 mol
c) Proportion:
Divide both mole amounts by the least of the two numbers, i.e. 0.0060
- CuSO₄: 0.0060 / 0.0060 = 1
- H₂O: 0.030 mol / 0.0060 = 5
Then, the ratio of CuSO₄ to H₂O is 1 : 5 and the chemical formula is:
Hence, the value of X is 5.